Advertisements
Advertisements
प्रश्न
A field is `16 1/2` m long and `12 2/5` m wide. Find the perimeter of the field.
उत्तर
Length of field = `16 1/2` m
Breadth of field = `12 2/5` m
∴ Perimeter of field = 2 (l + b)
`= 2 xx (16 1/2 + 12 2/5)`
`= 2 xx (33/2 + 62/5)`
`= 2 xx ((33 xx 5)/(2 xx 5) + (62 xx 2)/(5 xx 2))`
(∵ L.C.M. of 2 and 5 = 10)
`= 2 xx ((165 + 124)/10)`
`= 2 xx 289/10 = 289/5 "m" = 57 4/5 "m"`
APPEARS IN
संबंधित प्रश्न
Reduce to a single fraction:
`2 5/8 - 2 1/6 + 4 3/4`
Simplify: `9/12 xx 4/7`
Simplify: `2 div 1/3`
Simplify: `1 div 3/5`
Simplify: `- 5/8 div 3/4`
Simplify: `3 3/4 xx 1 1/5 xx 20/21`
Subtract: `2/9 "from" 4/5`
Simplify and reduce to a simple fraction:
`2/3 xx 1 1/4 div 3/7 "of" 2 5/8`
What should be subtracted from `8 3/4` to get `2 2/3`?
By what number should `5 5/6` be multiplied 1 to get `3 1/3`?
