Advertisements
Advertisements
Question
A field is `16 1/2` m long and `12 2/5` m wide. Find the perimeter of the field.
Solution
Length of field = `16 1/2` m
Breadth of field = `12 2/5` m
∴ Perimeter of field = 2 (l + b)
`= 2 xx (16 1/2 + 12 2/5)`
`= 2 xx (33/2 + 62/5)`
`= 2 xx ((33 xx 5)/(2 xx 5) + (62 xx 2)/(5 xx 2))`
(∵ L.C.M. of 2 and 5 = 10)
`= 2 xx ((165 + 124)/10)`
`= 2 xx 289/10 = 289/5 "m" = 57 4/5 "m"`
APPEARS IN
RELATED QUESTIONS
For the pair, given below, state whether it forms like fraction or unlike fraction:
`4/9 "and" 9/4`
Convert given fraction into a fraction with equal denominator:
`4/5, 17/20, 23/40 "and" 11/16`
Put the given fraction in ascending order by making denominator equal:
`1/3, 2/5, 3/4 "and" 1/6`
Insert three fractions between
`11/12 "and" 2/3`
Reduce to a single fraction:
`2 5/8 - 2 1/6 + 4 3/4`
Simplify: `2/3 xx 15`
Subtract: `1/8 "from" 5/8`
Subtract: `-4/7 "from" -6/11`
Find the value of `3/5 "of" 1 "hour"`
Simplify and reduce to a simple fraction:
`1/2 "of" 3/4 xx 1/2 div 2/3`
