Advertisements
Advertisements
प्रश्न
A map is drawn to scale of 1:20000. Find: The area of the lake on the map which has an actual area of 12km2
उत्तर
Scale = 1:20000
area of lake represented on the map:
12 Sq km =12 x (100 x 1000)2 [as 1km = 100000cm]
= 12 x 1010
`"Area(map)"/"Area(land)"` = Scale
`"Area(map)"/(12 xx 10^10) = (1)/(20000)^2`
Area(map) = `(12 xx 10^10)/(20000)^2 = (1200)/(4)`
Area(map) = 300cm2.
APPEARS IN
संबंधित प्रश्न
In the figure given below, Ray PT is bisector of ∠QPR. If PQ = 5.6 cm, QT = 4 cm and TR = 5 cm, find the value of x .
In figure, ABCD is a trapezium with AB || DC. If ∆AED is similar to ∆BEC, prove that AD = BC.
State, true or false:
All isosceles triangles are similar.
ΔABC~ΔPQR and ar(ΔABC) = 4, ar(ΔPQR) . If BC = 12cm, find QR.
In the given figure, DE║BC. If DE = 3cm, BC = 6cm and ar(ΔADE) = `15cm^2`, find the area of ΔABC.
In ΔABC, D and E are the mid-point on AB and AC such that DE || BC.
If AD = 8cm, AB = 12cm and AE = 12cm, find CE.
The dimensions of the model of a building are 1.2m x 75cm x 2m. If the scale factor is 1 : 20; find the actual dimensions of the building.
D is the mid point of side BC and AE ⊥ BC. If BC = a, AC = b, AB = c, ED = x, AD = p and AE = h, prove that c2 = `"p"^2 - "a"x + "a"^2/4`
There are two poles having heights 8 m and 4 m on plane ground as shown in fig. Because of sunlight shadows of smaller pole is 6m long, then find the length of shadow of longer pole.
It is given that ΔABC ~ ΔPQR, with `(BC)/(QR) = 1/3`. Then, `(ar(PRQ))/(ar(BCA))` is equal to ______.
