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प्रश्न
A mass of 200 g of mercury at 100°C is poured into water at 20°C. If the final temperature of the mixture is 25°C, find the mass of water. (Sp. heat cap. of mercury is 140 J/kgK).
उत्तर
Let the mass of water be m.
Heat lost by mercury = Heat gained by water
0.2 x 140 x (100 - 25) = m x 4200 x (25 - 20)
or, m = `(0.2 xx 140 xx 75)/(4200 xx 5)` = 0.1 kg = 100 g
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संबंधित प्रश्न
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Which has more heat: 1 g of ice at 0°C or 1 g of water at 0°C? Give reason.
1 kg of ice at 0o is heated at constant rate and its temperature is recorded after every 30 s till steam is formed at 100o C. Draw a temperature time graph to represent the change of phase.
200 g of hot water at 80°C is added to 300 g of cold water at 10 °C. Calculate the final temperature of the mixture of water. Consider the heat taken by the container to be negligible. [specific heat capacity of water is 4200 J kg-1 °C-1]
250 g of water at 30 °C is present in a copper vessel of mass 50 g. Calculate the mass of ice required to bring down the temperature of the vessel and its contents to 5 °C.
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