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A Wall 24 M , 0.4 M Thick and 6 M High is Constructed with the Bricks Each of Dimensions 25 Cm × 16 Cm × 10 Cm . - Mathematics

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प्रश्न

A wall 24 m , 0.4 m thick and 6 m high is constructed with the bricks each of dimensions 25 cm  \[\times\] 16 cm \[\times\] 10 cm . If the mortar occupies  \[\frac{1}{10}th\] of the volume of the wall, then find the number of bricks used in constructing the wall.

 
संक्षेप में उत्तर

उत्तर

Dimensions of the wall are 24 m × 0.4 m × 6 m
Volume of the wall = 24 m × 0.4 m × 6 m = 57.6 m3
Dimensions of the bricks are 25 m × 16 m × 10 m
Volume of each brick = 4000 cm3 = 0.004 m
Volume of mortar = \[\frac{1}{10} \times \text { Volume of the wall } = \frac{1}{10} \times 57 . 6 = 5 . 76 m^3\]

Volume of all the bricks = Volume of the wall − Volume of mortar

\[= 57 . 6 - 5 . 76\]

\[ = 51 . 84 m^3\]

Let the number of bricks used in making the wall be n.

\[\frac{\text { Volume of all the bricks }}{\text { Volume of each brick }} = n\]

\[ \Rightarrow \frac{51 . 84}{0 . 004} = n\]

\[ \Rightarrow n = 12960\]

Hence, 12960 bricks are used to make the wall.

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अध्याय 14: Surface Areas and Volumes - Exercise 14.3 [पृष्ठ ८५]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 14 Surface Areas and Volumes
Exercise 14.3 | Q 70 | पृष्ठ ८५

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If the volumes of two spheres are in the ratio 27 : 8, then their surface areas are in the ratio 3 : 2.

Reason (R)
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  3. Assertion (A) is true and Reason (R) is false.
  4. Assertion (A) is false and Reason (R) is true.

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