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Assertion (A) If the Volumes of Two Spheres Are in the Ratio 27 : 8, Then Their Surface Areas Are in the Ratio 3 : 2. Reason (R) Volume of a Sphere = 4 3 π R 3 Surface Area of a Sphere = 4πR2 - Mathematics

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प्रश्न

Assertion (A)
If the volumes of two spheres are in the ratio 27 : 8, then their surface areas are in the ratio 3 : 2.

Reason (R)
Volume of a sphere `=4/3pi"R"^3`
Surface area of a sphere = 4πR2


  1. Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).
  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).
  3. Assertion (A) is true and Reason (R) is false.
  4. Assertion (A) is false and Reason (R) is true.
योग

उत्तर

Assertion (A) is false and Reason (R) is true.
Assertion (A):

Let R and r be the radii of the two spheres.

Then, ratio of their volumes `=(4/3pi"R"^3)/(4/3 pi"r"^3)`

Therefore,

`=(4/3pi"R"^3)/(4/3 pi"r"^3) = 27/8`

`⇒ "R"^3/"r"^3 = 27/8`

`=> ("R"/"r")^3 = (3/2)^3`

`=> "R"/"r" = 3/2`

Hence, the ratio of their surface areas`= (4 pi"R"^2)/(4pi"r"^2)`

`="R"^2/"r"^2`

`=("R"/"r")^2`

`=(3/2)^2`

`=9/4`

= 9 : 4

Hence, Assertion (A) is false.

Reason (R): The given statement is true.

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अध्याय 19: Volume and Surface Area of Solids - Multiple Choice Questions [पृष्ठ ९२७]

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 19 Volume and Surface Area of Solids
Multiple Choice Questions | Q 79 | पृष्ठ ९२७

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