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Assertion (A) If the Volumes of Two Spheres Are in the Ratio 27 : 8, Then Their Surface Areas Are in the Ratio 3 : 2. Reason (R) Volume of a Sphere = 4 3 π R 3 Surface Area of a Sphere = 4πR2 - Mathematics

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Question

Assertion (A)
If the volumes of two spheres are in the ratio 27 : 8, then their surface areas are in the ratio 3 : 2.

Reason (R)
Volume of a sphere `=4/3pi"R"^3`
Surface area of a sphere = 4πR2


  1. Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).
  2. Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).
  3. Assertion (A) is true and Reason (R) is false.
  4. Assertion (A) is false and Reason (R) is true.
Sum

Solution

Assertion (A) is false and Reason (R) is true.
Assertion (A):

Let R and r be the radii of the two spheres.

Then, ratio of their volumes `=(4/3pi"R"^3)/(4/3 pi"r"^3)`

Therefore,

`=(4/3pi"R"^3)/(4/3 pi"r"^3) = 27/8`

`⇒ "R"^3/"r"^3 = 27/8`

`=> ("R"/"r")^3 = (3/2)^3`

`=> "R"/"r" = 3/2`

Hence, the ratio of their surface areas`= (4 pi"R"^2)/(4pi"r"^2)`

`="R"^2/"r"^2`

`=("R"/"r")^2`

`=(3/2)^2`

`=9/4`

= 9 : 4

Hence, Assertion (A) is false.

Reason (R): The given statement is true.

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Chapter 19: Volume and Surface Area of Solids - Multiple Choice Questions [Page 927]

APPEARS IN

RS Aggarwal Mathematics [English] Class 10
Chapter 19 Volume and Surface Area of Solids
Multiple Choice Questions | Q 79 | Page 927

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