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प्रश्न
Account for the following.
pKb of aniline is more than that of methylamine.
उत्तर
In aniline, the lone pair of electrons on the N-atom is delocalized over the benzene ring. As a result electron density on the nitrogen decreases. In contrast in CH3NH2, the +I effect of CH3 increases the electron density on the N-atom. Therefore, aniline is a weaker base than methylamine and hence its pKb value is more than that of methyl amine.
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संबंधित प्रश्न
Choose the most correct option.
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\[\ce{CH3 - C ≡ N ->[Na/C2H5OH] A ->[NaNO2/dilHCl]B}\]
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