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प्रश्न
Account for the following.
pKb of aniline is more than that of methylamine.
उत्तर
In aniline, the lone pair of electrons on the N-atom is delocalized over the benzene ring. As a result electron density on the nitrogen decreases. In contrast in CH3NH2, the +I effect of CH3 increases the electron density on the N-atom. Therefore, aniline is a weaker base than methylamine and hence its pKb value is more than that of methyl amine.
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संबंधित प्रश्न
Choose the most correct option.
Identify ‘B’ in the following reactions
\[\ce{CH3 - C ≡ N ->[Na/C2H5OH] A ->[NaNO2/dilHCl]B}\]
The product formed by the reaction an aldehyde with a primary amine ____________.
Arrange the following.
In decreasing order of basic strength
How will you prepare propan-1-amine from butane nitrile?
How will you convert diethylamine into N, N-diethyl acetamide?
\[\begin{array}{cc}
\ce{O}\phantom{.........}\\
||\phantom{.........}\\
\ce{H - \underset{(A)}{C} - NH - CH3}
\end{array}\]
and
\[\begin{array}{cc}
\ce{O}\\
||\\
\ce{CH3 - \underset{(B)}{C} - NH2}
\end{array}\]
are which type of isomers?
Define Amines.
Account for the following:
Aniline does not undergo Friedel-Crafts reaction.
Write short note on the following.
Ammonolysis
Write a short note on the following.
Ammonolysis
