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An emf of 96.0 mV is induced in the windings of a coil when the current in a nearby coil is increasing at the rate of 1.20 A/s. What is the mutual inductance (M) of the two coils? - Physics

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प्रश्न

An emf of 96.0 mV is induced in the windings of a coil when the current in a nearby coil is increasing at the rate of 1.20 A/s. What is the mutual inductance (M) of the two coils?

संख्यात्मक

उत्तर

Given:

e = 96 mV = 96 × 10-3 V, 

`"dI"/"dt"` = 1.20 A/s

To find: Mutual Inductance (M)

Formula: M = `|"e"|/|"dI""/""dt"|`

Calculation:

From formula

M = `(96 xx 10^-3)/1.2`

`= 80 xx 10^-3`

= 80 mH

Mutual Inductance of the two coils is 80 mH. 

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अध्याय 12: Electromagnetic Induction - Short Answer I

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एससीईआरटी महाराष्ट्र Physics [English] 12 Standard HSC
अध्याय 12 Electromagnetic Induction
Short Answer I | Q 4
बालभारती Physics [English] 12 Standard HSC Maharashtra State Board
अध्याय 12 Electromagnetic induction
Exercises | Q 13 | पृष्ठ २८७

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