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Aniline does not give Friedel-Crafts reaction. Give a reason. - Chemistry

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प्रश्न

Aniline does not give Friedel-Crafts reaction. Give a reason.

रासायनिक समीकरण/संरचनाएँ
कारण बताइए

उत्तर

Aniline does not undergo Friedel-Craft's reaction because the reaction takes place in the presence of AlCl3, but AlCl3 is a Lewis acid, whereas aniline is a strong basic. Thus, aniline interacts with AlCl3 to produce a salt.

The positive charge on the N-atom prevents electrophilic substitution in the benzene ring. As a result, aniline does not undergo the Friedel-Craft reaction.

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संबंधित प्रश्न

What is the action of the following reagents on aniline?

Bromine water


Give reasons for the following:

Aniline does not undergo Friedel- Crafts reaction.


Write the structures of main products when aniline reacts with the following reagents :

Br2 water


Write the chemical equations involved when aniline is treated with the following reagents:

Br2 water


Write short notes on acetylation.


What is the action of the following reagents on aniline?

Acetic anhydride

 


What is the action of the following reagents on aniline?

Hot and conc. sulphuric acid


Illustrate the following reactions giving suitable example in each case 

Acetylation of amines


How will you convert the following?

Aniline into N−phenylethanamide


What is the role of \[\ce{HNO3}\] in the nitrating mixture used for nitration of benzene?


A solution contains 1 g mol. each of p-toluene diazonium chloride and p-nitrophenyl diazonium chloride. To this 1 g mol. of alkaline solution of phenol is added. Predict the major product. Explain your answer.


Assertion: N, N-Diethylbenzene sulphonamide is insoluble in alkali.

Reason: Sulphonyl group attached to nitrogen atom is strong electron-withdrawing group.


When bromination of aniline is carried out by protecting – NH2. The major product is


Give reasons for the following observation:

Aniline is acetylated before nitration reaction.


Give reasons for the following observation:

Aniline does not react with methyl chloride in the presence of anhydrous AlCl3 catalyst.


In the following reaction, the reason for why meta-nitro product also formed is:


Assertion (A): Bromination of benzoic acid, gives m-bromobenzoic acid.

Reason (R): Carboxyl group increases the electron density at the meta position.


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