Advertisements
Advertisements
प्रश्न
At what height above the earth's surface would the value of acceleration due to gravity be half of what it is on the surface? Take the radius of earth to be R.
उत्तर
As we know
`g= GxxM/R^2`
So let at height H the value of g is half that of the earth earth surface
then g at R + H would be equal to
`g'= GxxM/(R+H)^2`
Now g'/g=1/2
1/2= R2/ (R+H)2
(R+H)2=2R2
R+H = √2 R
H = (√2-1) R
APPEARS IN
संबंधित प्रश्न
State Kepler’s law which is represented by the relation r3 ∝ T2.
At noon, the sun and the earth pull the objects on the earth's surface in opposite directions. At midnight, the sun and the earth pull these objects in same direction. Is the weight of an object, as measured by a spring balance on the earth's surface, more at midnight as compared to its weight at noon?
A tunnel is dug along a diameter of the earth. Find the force on a particle of mass m placed in the tunnel at a distance x from the centre.
Define one Newton. How much maximum acceleration can it produce in a mass of 1 kg?
What is meant by the equation :
`g= Gxxm/r^2`
where the symbols have their usual meanings.
What is the difference between gravity and gravitation?
State Newton's law of gravitation. What is the difference between:
g and G?
Give the applications of universal law gravitation.
Four identical particles of equal masses 1 kg made to move along the circumference of a circle of radius 1 m under the action of their own mutual gravitational attraction. The speed of each particle will be ______.
If three equal masses m are placed at the three vertices of an equilateral triangle of side 1/m then what force acts on a particle of mass 2m placed at the centroid?
