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Question
At what height above the earth's surface would the value of acceleration due to gravity be half of what it is on the surface? Take the radius of earth to be R.
Solution
As we know
`g= GxxM/R^2`
So let at height H the value of g is half that of the earth earth surface
then g at R + H would be equal to
`g'= GxxM/(R+H)^2`
Now g'/g=1/2
1/2= R2/ (R+H)2
(R+H)2=2R2
R+H = √2 R
H = (√2-1) R
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