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Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH3OH, CH3CN - Chemistry

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प्रश्न

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain.

Cyclohexane, KCl, CH3OH, CH3CN

संक्षेप में उत्तर

उत्तर

n-octane is a non-polar solvent. Therefore, the solubility of a non-polar solute is more than that of a polar solute in n-octane.

The order of increasing polarity is:

Cyclohexane < CH3CN < CH3OH < KCl

Therefore, the order of increasing solubility is:

KCl < CH3OH < CH3CN < Cyclohexane

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अध्याय 2: Solutions - Exercises [पृष्ठ ६१]

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एनसीईआरटी Chemistry [English] Class 12
अध्याय 2 Solutions
Exercises | Q 24 | पृष्ठ ६१

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