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By completing the following activity, examine the function f(x) = x3 – 9x2 + 24x for maxima and minima Solution: f(x) = x3 – 9x2 + 24x ∴ f'(x) = □ ∴ f''(x) = □ For extreme values, f'(x) = 0, we get x - Mathematics and Statistics

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प्रश्न

By completing the following activity, examine the function f(x) = x3 – 9x2 + 24x for maxima and minima

Solution: f(x) = x3 – 9x2 + 24x

∴ f'(x) = `square`

∴ f''(x) = `square`

For extreme values, f'(x) = 0, we get

x = `square` or `square`

∴ f''`(square)` = – 6 < 0

∴ f(x) is maximum at x = 2.

∴ Maximum value = `square`

∴ f''`(square)` = 6 > 0

∴ f(x) is maximum at x = 4.

∴ Minimum value = `square`

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योग

उत्तर

f(x) = x3 – 9x2 + 24x

∴ f'(x) = 3x2 – 18x + 24

∴ f''(x) = 6x – 18

For extreme values, f'(x) = 0, we get

3x2 – 18x + 24

∴ x2 – 6x + 8 = 0

∴ x2 – 4x – 2x + 8 = 0

∴ x(x – 4) – 2(x – 4) = 0

∴ (x – 4)(x – 2) = 0

x = 2 or 4

∴ f''(2) =  6(2) – 18

= 12 – 18

= – 6 < 0 

∴ f(x) is maximum at x = 2.

∴ Maximum value = f(2)

= (2)3 – 9(2)2 + 24(2)

= 8 – 36 + 48

20

∴ f''(4) = 6(4) – 18

= 24 – 18

= 6 > 0

∴ f(x) is maximum at x = 4.

∴ Minimum value = f(4)

= (4)3 – 9(4)2 + 24(4)

= 64 – 144 + 96

16

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अध्याय 1.4: Applications of Derivatives - Q.6

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