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प्रश्न
Calculate the oxidation number of phosphorus in the following species.
\[\ce{HPO^{2-}3}\]
उत्तर
Let the oxidation number of P in \[\ce{HPO^{2-}3}\] be x.
Therefore, +1 + x + (– 6) = – 2
x = +3
Oxidation number of phosphorus is +3.
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संबंधित प्रश्न
Assign oxidation numbers to the underlined element in the following species:
NaH2PO4
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H4P2O7
What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?
CH3CH2OH
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2SO4}\]
Match Column I with Column II for the oxidation states of the central atoms.
| Column I | Column II |
| (i) \[\ce{Cr2O^{2-}7}\] | (a) + 3 |
| (ii) \[\ce{MnO^{-}4}\] | (b) + 4 |
| (iii) \[\ce{VO^{-}3}\] | (c) + 5 |
| (iv) \[\ce{FeF^{3-}6}\] | (d) + 6 |
| (e) + 7 |
Match Column I with Column II for the oxidation states of the central atoms.
| Column I | Column II | |
| (i) | Ions having positive charge | (a) +7 |
| (ii) | The sum of oxidation number of all atoms in a neutral molecule |
(b) –1 |
| (iii) | Oxidation number of hydrogen ion \[\ce{(H+)}\] | (c) +1 |
| (iv) | Oxidation number of fluorine in \[\ce{NaF}\] | (d) 0 |
| (v) | Ions having negative charge | (e) Cation |
| (f) Anion |
The oxidation number of P in Mg2P207 is ____________.
In which of the following species oxidation number of the element(s) is equal to + 4?
In which of the following species, the oxidation number of the atom of the underlined elements is/are equal to +1?
On reaction with a stronger oxidizing agent like KIO4, hydrogen peroxide with the evolution of O2. The oxidation number of I in KIO4 changes to ______.
