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What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results? CH3CH2OH - Chemistry

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प्रश्न

What are the oxidation numbers of the underlined elements in the following and how do you rationalise your results?

CH3CH2OH

संख्यात्मक

उत्तर

CH3CH2OH

2(x) + 6(+1) + 1(-2) = 0 or 2x + 4 = 0

or x = -2

Hence, the O.N. of C is –2.

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Oxidation Number - Introduction
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Redox Reactions - EXERCISES [पृष्ठ २८०]

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एनसीईआरटी Chemistry - Part 1 and 2 [English] Class 11
अध्याय 8 Redox Reactions
EXERCISES | Q 8.2 - (d) | पृष्ठ २८०

संबंधित प्रश्न

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Match Column I with Column II for the oxidation states of the central atoms.

Column I Column II
(i) \[\ce{Cr2O^{2-}7}\] (a) + 3
(ii) \[\ce{MnO^{-}4}\] (b) + 4
(iii) \[\ce{VO^{-}3}\] (c) + 5
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  (e) + 7

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(ii) The sum of oxidation number
of all atoms in a neutral molecule
(b) –1
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(iv) Oxidation number of fluorine in \[\ce{NaF}\] (d) 0
(v) Ions having negative charge (e) Cation
    (f) Anion

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