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प्रश्न
In which of the following compounds, an element exhibits two different oxidation states.
विकल्प
\[\ce{NH2OH}\]
\[\ce{NH4NO3}\]
\[\ce{N2H4}\]
\[\ce{N3H}\]
उत्तर
\[\ce{NH4NO3}\]
Explanation:
The oxidation states are given below:
In \[\ce{NH2OH}\] oxidation of N is – 1.
\[\ce{NH4NO3}\] exists as \[\ce{NH^{+}4 . NO^{-}3}\],
Thus, the oxidation state of N in \[\ce{NH^{+}4}\] is – 3 while in \[\ce{NO^{-}3}\] is + 5.
In \[\ce{N2H4}\] oxidation of N is – 2
In \[\ce{N2H}\] oxidation of N is `(-1)/3`.
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संबंधित प्रश्न
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| Column I | Column II |
| (i) \[\ce{Cr2O^{2-}7}\] | (a) + 3 |
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| (iii) \[\ce{VO^{-}3}\] | (c) + 5 |
| (iv) \[\ce{FeF^{3-}6}\] | (d) + 6 |
| (e) + 7 |
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