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Chapters
2: Structure of Atom
3: Classification of Elements and Periodicity in Properties
4: Chemical Bonding and Molecular Structure
5: States of Matter
6: Thermodynamics
7: Equilibrium
▶ 8: Redox Reactions
9: Hydrogen
10: The s-block Elements
11: The p-block Elements
12: Organic Chemistry Some Basic Principles and Techniques
13: Hydrocarbons
14: Environmental Chemistry
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Solutions for Chapter 8: Redox Reactions
Below listed, you can find solutions for Chapter 8 of CBSE NCERT Exemplar for Chemistry [English] Class 11.
NCERT Exemplar solutions for Chemistry [English] Class 11 8 Redox Reactions Multiple Choice Questions (Type - I) [Pages 104 - 110]
Which of the following is not an example of redox reaction?
\[\ce{CuO + H2 -> Cu + H2O}\]
\[\ce{Fe2O3 + 3CO -> 2Fe + 3CO2}\]
\[\ce{2K + F2 -> 2KF}\]
\[\ce{BaCl2 + H2SO4 -> BaSO4 + 2HCl}\]
The more positive the value of EΘ, the greater is the tendency of the species to get reduced. Using the standard electrode potential of redox couples given below find out which of the following is the strongest oxidising agent.
EΘ values: \[\ce{Fe^{3+} / Fe^{2+} = + 0.77; I2 (s) / I- = + 0.54}\];
\[\ce{Cu^{2+} / Cu = + 0.34; Ag+ / Ag = + 0.80V}\]
\[\ce{Fe^{3+}}\]
\[\ce{I2(s)}\]
\[\ce{Cu^{2+}}\]
\[\ce{Ag+}\]
EΘ values of some redox couples are given below. On the basis of these values.
EΘ values: \[\ce{Br2 /Br- = + 1.90; Ag+ / Ag(s) = + 0.80}\];
\[\ce{Cu^{2+} / Cu(s) = + 0.34; I2(s) / I- = 0.54}\]
\[\ce{Cu}\] will reduce \[\ce{Br-}\]
\[\ce{Cu}\] will reduce \[\ce{Ag}\]
\[\ce{Cu}\] will reduce \[\ce{I-}\]
\[\ce{Cu}\] will reduce \[\ce{Br2}\]
Using the standard electrode potential, find out the pair between which redox reaction is not feasible.
EΘ values: \[\ce{Fe^{3+} / Fe^{2+} = + 0.77; I2/I- = + 0.54}\];
\[\ce{Cu^{2+} / Cu = + 0.34; Ag+ / Ag = + 0.80 V}\]
\[\ce{Fe^{3+} and I-}\]
\[\ce{Ag+ and Cu}\]
\[\ce{Fe^{3+} and Cu}\]
\[\ce{Ag and Fe^{3+}}\]
Thiosulphate reacts differently with iodine and bromine in the reactions given below:
\[\ce{2S2O^{2-}3 + I2 -> S4O^{2-}6 + 2I-}\]
\[\ce{S2O^{2-}3 + 2Br2 + 5H2O -> 2SO^{2-}4 + 2Br- + 10H+}\]
Which of the following statements justifies the above dual behaviour of thiosulphate?
Bromine is a stronger oxidant than iodine.
Bromine is a weaker oxidant than iodine.
Thiosulphate undergoes oxidation by bromine and reduction by iodine in these reactions.
Bromine undergoes oxidation and iodine undergoes reduction in these reactions.
The oxidation number of an element in a compound is evaluated on the basis of certain rules. Which of the following rules is not correct in this respect?
The oxidation number of hydrogen is always +1.
The algebraic sum of all the oxidation numbers in a compound is zero.
An element in the free or the uncombined state bears oxidation number zero.
In all its compounds, the oxidation number of fluorine is – 1.
In which of the following compounds, an element exhibits two different oxidation states.
\[\ce{NH2OH}\]
\[\ce{NH4NO3}\]
\[\ce{N2H4}\]
\[\ce{N3H}\]
Which of the following arrangements represent increasing oxidation number of the central atom?
\[\ce{CrO^{-}2, ClO^{-}3, CrO^{2-}4, MnO^{-}4}\]
\[\ce{ClO^{-}3, CrO^{2-}4, MnO^{-}4, CrO^{-}2}\]
\[\ce{CrO^{-}2, ClO^{-}3, MnO^{-}4, CrO^{2-}4}\]
\[\ce{CrO^{2-}4, MnO^{-}4, CrO^{-}2, ClO^{-}3}\]
The largest oxidation number exhibited by an element depends on its outer electronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number?
3d14s2
3d34s2
3d54s1
3d54s2
Identify disproportionation reaction
\[\ce{CH4 + 2O2 -> CO2 + 2H2O}\]
\[\ce{CH4 + 4Cl2 -> CCl4 + 4HCl}\]
\[\ce{2F2 + 2OH- -> 2F- + OF2 + H2O}\]
\[\ce{2NO2 + 2OH- -> NO^{-}2 + NO^{-}3 + H2O}\]
Which of the following elements does not show disproportionation tendency?
\[\ce{Cl}\]
\[\ce{Br}\]
\[\ce{F}\]
\[\ce{I}\]
Which of the following statement(s) is/are not true about the following decomposition reaction.
\[\ce{2KClO3 -> 2KCl + 3O2}\]
(i) Potassium is undergoing oxidation.
(ii) Chlorine is undergoing oxidation.
(iii) Oxygen is reduced.
(iv) None of the species are undergoing oxidation or reduction.
Identify the correct statement (s) in relation to the following reaction:
\[\ce{Zn + 2HCl -> ZnCl2 + H2}\]
(i) Zinc is acting as an oxidant.
(ii) Chlorine is acting as a reductant.
(iii) Hydrogen ion is acting as an oxidant.
(iv) Zinc is acting as a reductant.
The exhibition of various oxidation states by an element is also related to the outer orbital electronic configuration of its atom. Atom(s) having which of the following outermost electronic configurations will exhibit more than one oxidation state in its compounds.
(i) 3s1
(ii) 3d14s2
(iii) 3d24s2
(iv) 3s23p3
Identify the correct statements with reference to the given reaction.
\[\ce{P4 + 3OH- + 3H2O -> PH3 + 3H2PO^{-}2}\]
(i) Phosphorus is undergoing reduction only.
(ii) Phosphorus is undergoing oxidation only.
(iii) Phosphorus is undergoing oxidation as well as reduction.
(iv) Hydrogen is undergoing neither oxidation nor reduction.
Which of the following electrodes will act as anodes, when connected to Standard Hydrogen Electrode?
(i) \[\ce{Al/Al^{3+}; E^Θ = –1.66}\]
(ii) \[\ce{Fe/Fe^{2+}; E^Θ = – 0.44}\]
(iii) \[\ce{Cu/Cu2+ ; E^Θ = + 0.34}\]
(iv) \[\ce{F2 (g)/2F– (aq); E^Θ = + 2.87}\]
The reaction \[\ce{Cl2 (g) + 2OH- (aq) -> ClO- (aq) + Cl- (aq) + H2O (l)}\] represents the process of bleaching. Identify and name the species that bleaches the substances due to its oxidising action.
\[\ce{MnO^{2-}4}\] undergoes disproportionation reaction in acidic medium but \[\ce{MnO^{-}4}\] does not. Give reason.
\[\ce{PbO}\] and \[\ce{PbO2}\] react with \[\ce{HCl}] according to following chemical equations:
\[\ce{2PbO + 4HCl -> 2PbCl2 + 2H2O}\]
\[\ce{PbO2 + 4HCl -> PbCl2 + Cl2 + 2H2O}\]
Why do these compounds differ in their reactivity?
Nitric acid is an oxidising agent and reacts with \[\ce{PbO}\] but it does not react with \[\ce{PbO2}\]. Explain why?
Write balanced chemical equation for the following reactions:
Permanganate ion \[\ce{(MnO^{-}4)}\] reacts with sulphur dioxide gas in acidic medium to produce \[\ce{Mn^{2+}}\] and hydrogen sulphate ion.
Write balanced chemical equation for the following reactions:
Reaction of liquid hydrazine \[\ce{(N2H4)}\] with chlorate ion \[\ce{(ClO^{-}3)}\] in basic medium produces nitric oxide gas and chloride ion in gaseous state.
Write balanced chemical equation for the following reactions:
Dichlorine heptaoxide \[\ce{(Cl2O7)}\] in gaseous state combines with an aqueous solution of hydrogen peroxide in acidic medium to give chlorite ion \[\ce{(ClO^{-}2)}\] and oxygen gas. (Balance by ion-electron method)
Calculate the oxidation number of phosphorus in the following species.
\[\ce{HPO^{2-}3}\]
Calculate the oxidation number of phosphorus in the following species.
\[\ce{PO^{3-}4}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2S2O3}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2S4O6}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2SO3}\]
Calculate the oxidation number of sulphur atom in the following compounds:
\[\ce{Na2SO4}\]
Balance the following equations by the oxidation number method.
\[\ce{Fe^{2+} + H^{+} + Cr2O^{2-}7 -> Cr^{3+} + Fe^{3+} + H2O}\]
Balance the following equations by the oxidation number method.
\[\ce{I2 + NO^{-}3 -> NO2 + IO^{-}3}\]
Balance the following equations by the oxidation number method.
\[\ce{I2 + S2O^{2-}3 -> I- + S4O^{2-}6}\]
Balance the following equations by the oxidation number method.
\[\ce{MnO2 + C2O^{2-}4 -> Mn^{2+} + CO2}\]
Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.
\[\ce{3HCl (aq) + HNO3 (aq) -> Cl2 (g) + NOCl (g) + 2H2O (l)}\]
Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.
\[\ce{HgCl2 (aq) + 2KI (aq) -> HgI2 (s) + 2KCl (aq)}\]
Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.
\[\ce{Fe2O3 (s) + 3CO (g) ->[Δ] 2Fe (s) + 3CO2 (g)}\]
Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.
\[\ce{PCl3 (l) + 3H2O (l) -> 3HCl (aq) + H3PO3 (aq)}\]
Identify the redox reactions out of the following reactions and identify the oxidising and reducing agents in them.
\[\ce{4NH3 (g) + 3O2 (g) -> 2N2 (g) + 6H2O (g)}\]
Balance the following ionic equations.
\[\ce{Cr2O^{2-}7 + H^{+} + I- -> Cr^{3+} + I2 + H2O}\]
Balance the following ionic equations.
\[\ce{Cr2O^{2-}7 + Fe^{2+} + H+ -> Cr^{3+} + Fe^{3+} + H2O}\]
Balance the following ionic equations.
\[\ce{MnO^{-}4 + SO^{2-}3 + H^{+} -> Mn^{2+} + SO^{2-}4 + H2O}\]
Balance the following ionic equations.
\[\ce{MnO^{-}4 + H^{+} + Br^{-} -> Mn^{2+} + Br2 + H2O}\]
Match Column I with Column II for the oxidation states of the central atoms.
Column I | Column II |
(i) \[\ce{Cr2O^{2-}7}\] | (a) + 3 |
(ii) \[\ce{MnO^{-}4}\] | (b) + 4 |
(iii) \[\ce{VO^{-}3}\] | (c) + 5 |
(iv) \[\ce{FeF^{3-}6}\] | (d) + 6 |
(e) + 7 |
Match Column I with Column II for the oxidation states of the central atoms.
Column I | Column II | |
(i) | Ions having positive charge | (a) +7 |
(ii) | The sum of oxidation number of all atoms in a neutral molecule |
(b) –1 |
(iii) | Oxidation number of hydrogen ion \[\ce{(H+)}\] | (c) +1 |
(iv) | Oxidation number of fluorine in \[\ce{NaF}\] | (d) 0 |
(v) | Ions having negative charge | (e) Cation |
(f) Anion |
Assertion (A): Among halogens fluorine is the best oxidant.
Reason (R): Fluorine is the most electronegative atom.
Both A and R are true and R is the correct explanation of A.
Both A and R are true but R is not the correct explanation of A.
A is true but R is false.
Both A and R are false.
Assertion (A): In the reaction between potassium permanganate and potassium iodide, permanganate ions act as oxidising agent.
Reason (R): Oxidation state of manganese changes from +2 to +7 during the reaction.
Both A and R are true and R is the correct explanation of A
Both A and R are true but R is not the correct explanation of A.
A is true but R is false.
Both A and R are false.
Assertion (A): The decomposition of hydrogen peroxide to form water and oxygen is an example of disproportionation reaction.
Reason (R): The oxygen of peroxide is in –1 oxidation state and it is converted to zero oxidation state in \[\ce{O2}\] and –2 oxidation state in \[\ce{H2O}\].
Both A and R are true and R is the correct explanation of A.
Both A and R are true but R is not the correct explanation of A.
A is true but R is false.
Both A and R are false.
Assertion (A): Redox couple is the combination of oxidised and reduced form of a substance involved in an oxidation or reduction half cell.
Reason (R): In the representation \[\ce{E^Θ_{Fe^{3+}/Fe^{2+}}}\] and \[\ce{E^Θ_{Cu^{2+}/Cu}, Fe^{3+}/Fe^{2+}}\] and \[\ce{Cu^{2+}/Cu}\] are redox couples.
Both A and R are true and R is the correct explanation of A.
Both A and R are true but R is not the correct explanation of A.
A is true but R is false.
Both A and R are false.
Explain redox reactions on the basis of electron transfer. Give suitable examples.
On the basis of standard electrode potential values, suggest which of the following reactions would take place? (Consult the book for EΘ value).
\[\ce{Cu + Zn^{2+} -> Cu^{2+} + Zn}\]
On the basis of standard electrode potential values, suggest which of the following reactions would take place? (Consult the book for EΘ value).
\[\ce{Mg + Fe^{2+} -> Mg^{2+} + Fe}\]
On the basis of standard electrode potential values, suggest which of the following reactions would take place? (Consult the book for EΘ value).
\[\ce{Br2 + 2Cl- -> Cl2 + 2Br-}\]
On the basis of standard electrode potential values, suggest which of the following reactions would take place? (Consult the book for EΘ value).
\[\ce{Fe + Cd^{2+} -> Cd + Fe^{2+}}\]
Why does fluorine not show disporportionation reaction?
Write redox couples involved in the reactions given.
\[\ce{Cu + Zn^{2+} ->Cu^{2+} + Zn}\]
Write redox couples involved in the reactions given.
\[\ce{Mg + Fe^{2+} -> Mg^{2+} + Fe}\]
Write redox couples involved in the reactions given.
\[\ce{Br2 + 2Cl- -> Cl2 + 2Br-}\]
Write redox couples involved in the reactions given.
\[\ce{Fe + Cd^{2+} -> Cd + Fe^{2+}}\]
Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine.
\[\ce{NaClO4, NaClO3, NaClO, KClO2, Cl2O7, ClO3, Cl2O, NaCl, Cl2 , ClO2}\].
Which oxidation state is not present in any of the above compounds?
Which method can be used to find out strength of reductant/oxidant in a solution? Explain with an example.
Solutions for 8: Redox Reactions
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NCERT Exemplar solutions for Chemistry [English] Class 11 chapter 8 - Redox Reactions
Shaalaa.com has the CBSE Mathematics Chemistry [English] Class 11 CBSE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT Exemplar solutions for Mathematics Chemistry [English] Class 11 CBSE 8 (Redox Reactions) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Chemistry [English] Class 11 chapter 8 Redox Reactions are Classical Idea of Redox Reactions - Oxidation and Reduction Reactions, Redox Reactions in Terms of Electron Transfer Reactions - Introduction, Redox Reactions in Terms of Electron Transfer Reactions - Competitive Electron Transfer Reactions, Oxidation Number - Introduction, Types of Redox Reactions, Balancing Redox Reactions in Terms of Loss and Gain of Electrons, Redox Reactions as the Basis for Titrations, Limitations of Concept of Oxidation Number, Redox Reactions and Electrode Processes.
Using NCERT Exemplar Chemistry [English] Class 11 solutions Redox Reactions exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Exemplar Solutions are essential questions that can be asked in the final exam. Maximum CBSE Chemistry [English] Class 11 students prefer NCERT Exemplar Textbook Solutions to score more in exams.
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