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प्रश्न
Can a galvanometer as such be used for measuring the current? Explain.
उत्तर
Yes a galvanometer can be used for measuring the current
Conversion of a galvanometer into an ammeter
A shunt (low resistance) is connected in parallel with a galvanometer.
`S=(I_g/(I-I_g))G`
Here,
I = total current in circuit
G = resistance of the galvanometer
S = resistance of the shunt
Ig = current through the galvanometer
संबंधित प्रश्न
Obtain the expression for current sensitivity of moving coil galvanometer.
- A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60° with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning.
- Would your answer change, if the circular coil in (a) were replaced by a planar coil of some irregular shape that encloses the same area? (All other particulars are also unaltered.)
Explain how moving coil galvanometer is converted into a voltmeter. Derive the necessary formula.
A moving coil galvanometer has a resistance of 25Ω and gives a full scale deflection for a current of 10mA. How will you convert it into a voltmeter having range 0 - 100 V?
Figure shows two circuits each having a galvanometer and a battery of 3V.
When the galvanometers in each arrangement do not show any deflection, obtain the ratio R1/R2.
In the meter bridge experiment, balance point was observed at J with AJ = l.
(i) The values of R and X were doubled and then interchanged. What would be the new position of balance point?
(ii) If the galvanometer and battery are interchanged at the balance position, how will the alance point get affected?
The coil of a moving coil galvanometer is wound over a metal frame in order to ______.
The current sensitivity of a galvanometer increase by 20%. If its resistance also increases by 25%, the voltage sensitivity will ______.
A moving coil galvanometer of resistance 55 Ω produces a full scale deflection for a current of 250 mA. How will you convert it into an ammeter with a range of 0 - 3A?
