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Choose the correct alternative: f y = f(x2 + 2) and f'(3) = 5 , then dddydx at x = 1 is - Mathematics

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प्रश्न

Choose the correct alternative:

f y = f(x2 + 2) and f'(3) = 5 , then `("d"y)/("d"x)` at x = 1 is

विकल्प

  • 5

  • 25

  • 15

  • 10

MCQ

उत्तर

10

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Differentiability and Continuity
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Differential Calculus - Differentiability and Methods of Differentiation - Exercise 10.5 [पृष्ठ १७७]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 10 Differential Calculus - Differentiability and Methods of Differentiation
Exercise 10.5 | Q 2 | पृष्ठ १७७

संबंधित प्रश्न

Find the derivatives of the following functions using first principle.

f(x) = – 4x + 7


Find the derivatives from the left and from the right at x = 1 (if they exist) of the following functions. Are the functions differentiable at x = 1?

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Find the derivatives from the left and from the right at x = 1 (if they exist) of the following functions. Are the functions differentiable at x = 1?

`f(x) = sqrt(1 - x^2)`


Determine whether the following function is differentiable at the indicated values.

f(x) = x |x| at x = 0


Determine whether the following function is differentiable at the indicated values.

f(x) = |x| + |x – 1| at x = 0, 1


Show that the following functions are not differentiable at the indicated value of x.

`f(x) = {{:(-x + 2, x ≤ 2),(2x - 4, x > 2):}` , x = 2


Show that the following functions are not differentiable at the indicated value of x.

`f(x) = {{:(3x",", x < 0),(-4x",", x ≥ 0):}` , x = 0


The graph of f is shown below. State with reasons that x values (the numbers), at which f is not differentiable.


If f(x) = |x + 100| + x2, test whether f’(–100) exists.


Examine the differentiability of functions in R by drawing the diagram

|sin x|


Choose the correct alternative:

If y = mx + c and f(0) = f’(0) = 1, then f(2) is


Choose the correct alternative:

If pv = 81, then `"dp"/"dv"` at v = 9 is


Choose the correct alternative:

If f(x) = `{{:(x + 1,  "when"   x < 2),(2x - 1,  "when"  x ≥ 2):}` , then f'(2) is


Choose the correct alternative:

If g(x) = (x2 + 2x + 1) f(x) and f(0) = 5 and `lim_(x -> 0) (f(x) - 5)/x` = 4, then g'(0) is


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