Advertisements
Advertisements
प्रश्न
Compare the modal ages of two groups of students appearing for an entrance test:
| Age (in years): | 16-18 | 18-20 | 20-22 | 22-24 | 24-26 |
| Group A: | 50 | 78 | 46 | 28 | 23 |
| Group B: | 54 | 89 | 40 | 25 | 17 |
उत्तर
| Age (in years) | Group ‘A’ | Group ‘B’ |
| 16–18 | 50 | 54 |
| 18–20 | 78 | 89 |
| 20–22 | 46 | 40 |
| 22–24 | 28 | 25 |
| 24–25 | 23 | 17 |
For group “A”
The maximum frequency is 78 so the modal class is 18–20.
Therefore,
l = 18
h = 2
f = 78
f1 = 50
f2 = 46
Mode `rArr=l+(f-f1)/(2f-f1-f2)xxh`
`=18+(78-50)/(156-50-46)xx2`
`=18+28/60xx2`
`=18+14/15`
= 18 + 0.93
= 18.93
For group “B”
The maximum frequency 89 so modal class 18–20.
Therefore,
l = 18
h = 2
f = 89
f1 = 54
f2 = 40
Mode `rArr=l+(f-f1)/(2f-f1-f2)xxh`
`=18+(89-54)/(178-54-40)xx2`
`=18+35/84xx2`
`=18+35/42`
`=18+5/6`
= 18 + 0.83
= 18.83
Thus, the modal age of group A is 18.93 years whereas the modal age of group B is 18.83 years.
APPEARS IN
संबंधित प्रश्न
The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.
| Number of students per teacher |
Number of states/U.T. |
| 15 − 20 | 3 |
| 20 − 25 | 8 |
| 25 − 30 | 9 |
| 30 − 35 | 10 |
| 35 − 40 | 3 |
| 40 − 45 | 0 |
| 45 − 50 | 0 |
| 50 − 55 | 2 |
Find the mode of the following data:
15, 8, 26, 25, 24, 15, 18, 20, 24, 15, 19, 15
Find the mode of the following distribution.
| Class-interval: | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | 70 - 80 |
| Frequency: | 5 | 8 | 7 | 12 | 28 | 20 | 10 | 10 |
Find the mode of the following distribution.
| Class-interval: | 25 - 30 | 30 - 35 | 35 - 40 | 40 - 45 | 45 - 50 | 50 - 55 |
| Frequency: | 25 | 34 | 50 | 42 | 38 | 14 |
Find the mean, median and mode of the following data:
| Classes: | 0-20 | 20-40 | 40-60 | 40-60 | 80-100 | 100-120 | 120-140 |
| Frequency: | 6 | 8 | 10 | 12 | 6 | 5 | 3 |
Heights of students of class X are givee in the flowing frequency distribution
| Height (in cm) | 150 – 155 | 155 – 160 | 160 – 165 | 165 – 170 | 170 - 175 |
| Number of students | 15 | 8 | 20 | 12 | 5 |
Find the modal height.
Also, find the mean height. Compared and interpret the two measures of central tendency.
Find the mode of the given data:
| Class Interval | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 |
| Frequency | 15 | 6 | 18 | 10 |
Construction of a cumulative frequency table is useful in determining the ______.
There are lottery tickets labelled numbers from 1 to 500. I want to find the number which is most common in the lottery tickets. What quantity do I need to use?
For the following distribution:
| Marks | Number of students |
| Below 10 | 3 |
| Below 20 | 12 |
| Below 30 | 27 |
| Below 40 | 57 |
| Below 50 | 75 |
| Below 60 | 80 |
The modal class is ______.
