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The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures. - Mathematics

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प्रश्न

The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.

Number of students
per teacher
Number of states/U.T.
15 − 20 3
20 − 25 8
25 − 30 9
30 − 35 10
35 − 40 3
40 − 45 0
45 − 50 0
50 − 55 2
योग

उत्तर

It can be observed from the given data that the maximum class frequency is 10 belonging to class interval 30 − 35.

Therefore, modal class = 30 − 35

Class size (h) = 5

lower limit (l) of modal class is =  30

Frequency (f1) of modal class = 10

Frequency (f0) of the preceding modal class = 9

Frequency (f2) of the succeeding modal class = 3

`Mode = l+((f_1-f_0)/(2f_1-f_0-f_2) xxh)`

= `30+((10-9)/2(10)-9-3)xx(5)`

=`30+(1/(20-12))xx 5`

=` 30 + 5/8`

= 30.625

Mode = 30.6

It represents that most of the states and U.T. have a teacher-student ratio as 30.6.

To find the class marks, the following relation is used:

`"Class mark" = ("Upper class limit + Lower class limit")/2`

Taking 32.5 as the assumed mean (a), di, ui, and fiui are calculated as follows:

Number of students
per teacher

Number of states/U.T. (fi)

xi di = xi − 32. `u_i=d_i/5` fiui
15 − 20 3 17.5 −15 −3 −9
20 − 25 8 22.5 -10 −2 −16
25 − 30 9 27.5 − 5 −1 −9
30 − 35 10 32.5 0 0 0
35 − 40 3 37.5 5 1 3
40 − 45 0 42.5 10 2 0
45 − 50 0 47.5 15 3 0
50 − 55 2 52.5 20 4 8
Total 35       -23

Mean, `barx = a+((sumf_iu_i)/(sumf_i))xxh`

= `32.5 +((-23)/35)xx5`

= `32.5 - 23/7 `

= 32.5 - 3.28

= 29.22

Therefore, the mean of the data is 29.2.

It represents that, on average, the teacher-student ratio was 29.2

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अध्याय 14: Statistics - Exercise 14.2 [पृष्ठ २७६]

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एनसीईआरटी Mathematics [English] Class 10
अध्याय 14 Statistics
Exercise 14.2 | Q 4 | पृष्ठ २७६
आरडी शर्मा Mathematics [English] Class 10
अध्याय 15 Statistics
Exercise 15.5 | Q 10 | पृष्ठ ४६

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