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प्रश्न
The following distribution gives the state-wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.
Number of students per teacher |
Number of states/U.T. |
15 − 20 | 3 |
20 − 25 | 8 |
25 − 30 | 9 |
30 − 35 | 10 |
35 − 40 | 3 |
40 − 45 | 0 |
45 − 50 | 0 |
50 − 55 | 2 |
उत्तर
It can be observed from the given data that the maximum class frequency is 10 belonging to class interval 30 − 35.
Therefore, modal class = 30 − 35
Class size (h) = 5
lower limit (l) of modal class is = 30
Frequency (f1) of modal class = 10
Frequency (f0) of the preceding modal class = 9
Frequency (f2) of the succeeding modal class = 3
`Mode = l+((f_1-f_0)/(2f_1-f_0-f_2) xxh)`
= `30+((10-9)/2(10)-9-3)xx(5)`
=`30+(1/(20-12))xx 5`
=` 30 + 5/8`
= 30.625
Mode = 30.6
It represents that most of the states and U.T. have a teacher-student ratio as 30.6.
To find the class marks, the following relation is used:
`"Class mark" = ("Upper class limit + Lower class limit")/2`
Taking 32.5 as the assumed mean (a), di, ui, and fiui are calculated as follows:
Number of students per teacher |
Number of states/U.T. (fi) |
xi | di = xi − 32. | `u_i=d_i/5` | fiui |
15 − 20 | 3 | 17.5 | −15 | −3 | −9 |
20 − 25 | 8 | 22.5 | -10 | −2 | −16 |
25 − 30 | 9 | 27.5 | − 5 | −1 | −9 |
30 − 35 | 10 | 32.5 | 0 | 0 | 0 |
35 − 40 | 3 | 37.5 | 5 | 1 | 3 |
40 − 45 | 0 | 42.5 | 10 | 2 | 0 |
45 − 50 | 0 | 47.5 | 15 | 3 | 0 |
50 − 55 | 2 | 52.5 | 20 | 4 | 8 |
Total | 35 | -23 |
Mean, `barx = a+((sumf_iu_i)/(sumf_i))xxh`
= `32.5 +((-23)/35)xx5`
= `32.5 - 23/7 `
= 32.5 - 3.28
= 29.22
Therefore, the mean of the data is 29.2.
It represents that, on average, the teacher-student ratio was 29.2
संबंधित प्रश्न
The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.
Runs scored | Number of batsmen |
3000 − 4000 | 4 |
4000 − 5000 | 18 |
5000 − 6000 | 9 |
6000 − 7000 | 7 |
7000 − 8000 | 6 |
8000 − 9000 | 3 |
9000 − 10000 | 1 |
10000 − 11000 | 1 |
Find the mode of the data.
A student noted the number of cars passing through a spot on a road for 100 periods each of 3 minutes and summarised it in the table given below. Find the mode of the data.
Number of cars | 0 − 10 | 10 − 20 | 20 − 30 | 30 − 40 | 40 − 50 | 50 − 60 | 60 − 70 | 70 − 80 |
Frequency | 7 | 14 | 13 | 12 | 20 | 11 | 15 | 8 |
The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
Monthly consumption (in units) | Number of consumers |
65 - 85 | 4 |
85 - 105 | 5 |
105 - 125 | 13 |
125 - 145 | 20 |
145 - 165 | 14 |
165 - 185 | 8 |
185 - 205 | 4 |
The following is the distribution of height of students of a certain class in a certain city:
Height (in cm): | 160 - 162 | 163 - 165 | 166 - 168 | 169 - 171 | 172 - 174 |
No. of students: | 15 | 118 | 142 | 127 | 18 |
Find the average height of maximum number of students.
Find the mean, median and mode of the following data:
Classes: | 0-20 | 20-40 | 40-60 | 40-60 | 80-100 | 100-120 | 120-140 |
Frequency: | 6 | 8 | 10 | 12 | 6 | 5 | 3 |
Compute the mode of the following data:
Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
Frequency | 25 | 16 | 28 | 20 | 5 |
Find the mode of the given data:
Class Interval | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 |
Frequency | 15 | 6 | 18 | 10 |
The frequency distribution for agriculture holdings in a village is given below:
Area of land (in hectares) | 1 – 3 | 3 – 5 | 5 – 7 | 7 – 9 | 9 – 11 | 11 – 13 |
Number of families | 20 | 45 | 80 | 55 | 40 | 12 |
Find the modal agriculture holding per family.
If the mode of the data: 64, 60, 48, x, 43, 48, 43, 34 is 43, then x + 3 =
If the mode of the data: 16, 15, 17, 16, 15, x, 19, 17, 14 is 15, then x =
Find the mode from the following information:
L = 10, h = 2, f0 = 58, f1 = 70, f2 = 42.
The following table give the marks scored by students in an examination:
Marks | 0 - 5 | 5 - 10 | 10 - 15 | 15 - 20 | 20 - 25 | 25 - 30 | 30 - 35 | 35 - 40 |
No. of students | 3 | 7 | 15 | 24 | 16 | 8 | 5 | 2 |
(i) Find the modal group
(ii) Which group has the least frequency?
Mode is the ______.
The monthly income of 100 families are given as below:
Income (in Rs) | Number of families |
0 – 5000 | 8 |
5000 – 10000 | 26 |
10000 – 15000 | 41 |
15000 – 20000 | 16 |
20000 – 25000 | 3 |
25000 – 30000 | 3 |
30000 – 35000 | 2 |
35000 – 40000 | 1 |
Calculate the modal income.
If L = 10, f1 = 70, f0 = 58, f2 = 42, h = 2, then find the mode by using formula.
For the following distribution:
Class | 0 - 5 | 5 - 10 | 10 - 15 | 15 - 20 | 20 - 25 |
Frequency | 10 | 15 | 12 | 20 | 9 |
the upper limit of the modal class is:
The mode of a grouped frequency distribution is 75 and the modal class is 65-80. The frequency of the class preceding the modal class is 6 and the frequency of the class succeeding the modal class is 8. Find the frequency of the modal class.
For the following distribution:
Class | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 |
Frequency | 10 | 15 | 12 | 20 | 9 |
The lower limit of modal class is:
The upper limit of the modal class of the given distribution is:
Height [in cm] | Below 140 | Below 145 | Below 150 | Below 155 | Below 160 | Below 165 |
Number of girls | 4 | 11 | 29 | 40 | 46 | 51 |
The following frequency distribution table shows the classification of the number of vehicles and the volume of petrol filled in them. To find the mode of the volume of petrol filled, complete the following activity:
Class (Petrol filled in Liters) |
Frequency (Number of Vehicles) |
0.5 - 3.5 | 33 |
3.5 - 6.5 | 40 |
6.5 - 9.5 | 27 |
9.5 - 12.5 | 18 |
12.5 - 15.5 | 12 |
Activity:
From the given table,
Modal class = `square`
∴ Mode = `square + [(f_1 - f_0)/(2f_1 -f_0 - square)] xx h`
∴ Mode = `3.5 + [(40 - 33)/(2(40) - 33 - 27)] xx square`
∴ Mode = `3.5 +[7/(80 - 60)] xx 3`
∴ Mode = `square`
∴ The mode of the volume of petrol filled is `square`.