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The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them. - Mathematics

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प्रश्न

The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.

Monthly consumption (in units) Number of consumers
65 - 85 4
85 - 105 5
105 - 125 13
125 - 145 20
145 - 165 14
165 - 185 8
185 - 205 4
योग

उत्तर

The given data is shown below.

Monthly Consumption (in units) No. of consumers (fi) xi fixi C.f.
65−85 4 75 300 4
85−105 5 95 475 9
105−125 13 115 1495 22
125−145 20 135 2700 42
145−165 14 155 2170 56
165−185 8 175 1400 64
185−205 4 195 780 68
Total `sumf=68`   `sumf_1x_1=9320`  

Here, the maximum frequency is 20 so the modal class is 125 − 145.

Therefore,

l = 125, h = 20, f = 20, f1 = 13 and f2 = 14

Mode `=l+(f-f_1)/(2f-f_1-f_2)xxh`

`=125+7/13xx20`

`=125+140/13`

= 125 + 10.76

= 135.76

Mode = 135.76 units

Thus, the mode of the monthly consumption of electricity is 135.76 units.

Mean `=(sumf_1x_1)/(sumf)`

`=9320/68=137.05`

Mean = 137.05

Thus, the mean of the monthly consumption of electricity is 137.05 units.

Here,

Total number of consumers, N = 68 (even)

Then, `N/2=34`

Median `=l+(N/2_f)/fxxh`

`=125+(68/2_22)/20xx20`

`=125+(34-22)/20xx20`

`=125+12/20xx20`

= 125 + 12

 = 137

Thus, the median of the monthly consumption of electricity is 137 units.

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अध्याय 14: Statistics - Exercise 14.3 [पृष्ठ २८७]

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एनसीईआरटी Mathematics [English] Class 10
अध्याय 14 Statistics
Exercise 14.3 | Q 1 | पृष्ठ २८७
आरडी शर्मा Mathematics [English] Class 10
अध्याय 15 Statistics
Exercise 15.5 | Q 13 | पृष्ठ ४६

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