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प्रश्न
Compute the mode from the following data:
Class interval | 1 – 5 | 6 – 10 | 11 – 15 | 16 – 20 | 21 – 25 | 26 – 30 | 31 – 35 | 36 – 40 | 41 – 45 | 46 – 50 |
Frequency | 3 | 8 | 13 | 18 | 28 | 20 | 13 | 8 | 6 | 4 |
उत्तर
Clearly, we have to find the mode of the data. The given data is an inclusive series. So, we will convert it to an exclusive form as given below:
Class interval | 0.5 – 5.5 | 5.5 – 10.5 | 10.5 – 15.5 | 15.5 – 20.5 | 20.5 – 25.5 | 25.5 – 30.5 | 30.5 – 35.5 | 35.5 – 40.5 | 40.5 – 45.5 | 45.5 – 50.5 |
Frequency | 3 | 8 | 13 | 18 | 28 | 20 | 13 | 8 | 6 | 4 |
As the class 20.5 – 25.5 has the maximum frequency, it is the modal class.
Now, `x_k = 20.5, h = 5, f_k = 28, f_k-1 = 18, f_k+1 = 20`
∴ Mode, `M_0 = x_k + {ℎ × ((f_k− f_k−1))/((2f_k− f_k−1−f_k+1))}`
`= 20.5 + {5 × ((28−18))/((2×28−18−20))}`
`= 20.5 + {5× 10/18}`
= (20.5 + 2.78)
= 23.28
Hence, mode = 23.28
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संबंधित प्रश्न
The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
Monthly consumption (in units) | Number of consumers |
65 - 85 | 4 |
85 - 105 | 5 |
105 - 125 | 13 |
125 - 145 | 20 |
145 - 165 | 14 |
165 - 185 | 8 |
185 - 205 | 4 |
Find the mode of the following distribution:
Marks | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
Frequency | 12 | 35 | 45 | 25 | 13 |
If the mode of the data: 16, 15, 17, 16, 15, x, 19, 17, 14 is 15, then x =
Find the mode from the following information:
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The following table give the marks scored by students in an examination:
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No. of students | 3 | 7 | 15 | 24 | 16 | 8 | 5 | 2 |
(i) Find the modal group
(ii) Which group has the least frequency?
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₹ 5000, ₹ 7000, ₹ 5000, ₹ 7000, ₹ 8000, ₹ 7000, ₹ 7000, ₹ 8000, ₹ 7000, ₹ 5000
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0.5 - 3.5 | 33 |
3.5 - 6.5 | 40 |
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Activity:
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