Advertisements
Advertisements
प्रश्न
If mode of the following frequency distribution is 55, then find the value of x.
| Class | 0 – 15 | 15 – 30 | 30 – 45 | 45 – 60 | 60 – 75 | 75 – 90 |
| Frequency | 10 | 7 | x | 15 | 10 | 12 |
उत्तर
Given: Mode of frequency distribution = 55
So, modal class is 45 – 60
Lower limit (l) = 45
Class interval (h) = 15
Also, `f_0` = 15, `f_1` = x and `f_2` = 10
Mode = `l + ((f_0 - f_1)/(2f_0 - f_1 - f_2)) xx h`
⇒ 55 = `45 + ((15 - x)/(30 - x - 10)) xx 15`
⇒ 55 – 45 = `(15(15 - x))/(30 - x - 10)`
⇒ 10(30 – x – 10) = 225 – 15x
⇒ 300 –10x – 100 = 225 – 15x
⇒ 5x = 25
⇒ x = 5
APPEARS IN
संबंधित प्रश्न
The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
| Monthly consumption (in units) | Number of consumers |
| 65 - 85 | 4 |
| 85 - 105 | 5 |
| 105 - 125 | 13 |
| 125 - 145 | 20 |
| 145 - 165 | 14 |
| 165 - 185 | 8 |
| 185 - 205 | 4 |
The following is the distribution of height of students of a certain class in a certain city:
| Height (in cm): | 160 - 162 | 163 - 165 | 166 - 168 | 169 - 171 | 172 - 174 |
| No. of students: | 15 | 118 | 142 | 127 | 18 |
Find the average height of maximum number of students.
Find the mean, median and mode of the following data:
| Classes: | 0 – 50 | 50 – 100 | 100 – 150 | 150 – 200 | 200 – 250 | 250 – 300 | 300 – 350 |
| Frequency: | 2 | 3 | 5 | 6 | 5 | 3 | 1 |
The following frequency table shows the demand for a sweet and the number of customers. Find the mode of demand of sweet.
|
Weight of sweet (gram)
|
0 - 250 | 250 - 500 | 500 - 750 | 750 - 1000 | 1000 - 1250 |
| No. of customers | 10 | 60 | 25 | 20 | 15 |
Calculate the mode of the following distribution:
| Class | 10 − 15 | 15 − 20 | 20 − 25 | 25 − 30 | 30 − 35 |
| Frequency | 4 | 7 | 20 | 8 | 1 |
For the following distribution
| C.I. | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
| F | 20 | 30 | 24 | 40 | 18 |
the sum of lower limits of the modal class and the median class is?
For the following distribution
| Monthly Expenditure (Rs.) | No. of families |
| Expenditure less than Rs. 10,000 | 15 |
| Expenditure les than Rs. 13,000 | 31 |
| Expenditure les than Rs. 16,000 | 50 |
| Expenditure les than Rs. 19,000 | 67 |
| Expenditure les than Rs. 22,000 | 85 |
| Expenditure les than Rs. 25,000 | 100 |
The number of families having expenditure range (in ?) 16,000 - 19,000 is?
There are lottery tickets labelled numbers from 1 to 500. I want to find the number which is most common in the lottery tickets. What quantity do I need to use?
For the following distribution:
| Class | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 |
| Frequency | 10 | 15 | 12 | 20 | 9 |
The sum of lower limits of the median class and modal class is:
The mode of the numbers 2, 3, 3, 4, 5, 4, 4, 5, 3, 4, 2, 6, 7 is ______.
