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प्रश्न
The following frequency table shows the demand for a sweet and the number of customers. Find the mode of demand of sweet.
|
Weight of sweet (gram)
|
0 - 250 | 250 - 500 | 500 - 750 | 750 - 1000 | 1000 - 1250 |
| No. of customers | 10 | 60 | 25 | 20 | 15 |
उत्तर
The maximum class frequency is 60.
The class corresponding to this frequency is 250 - 500.
So, the modal class is 250 - 500.
L (the lower limit of modal class) = 250
f1 (frequency of the modal class) = 60
fo (frequency of the class preceding the modal class) = 10
f2 (frequency of the class succeeding the modal class) = 25
h (class size) = 250
Mode = `L + ((f_1-f_0)/(2f_1-f_0-f_2))xx h`
`= 250+((60-10)/(2xx60-10-25)) xx 250`
= 250 + 147.06
= 397.06
Hence, the modal demand of sweet is 397.06 grams.
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संबंधित प्रश्न
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| Expenditure (in Rs) | Number of families |
| 1000 − 1500 | 24 |
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| 2000 − 2500 | 33 |
| 2500 − 3000 | 28 |
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| 3500 − 4000 | 22 |
| 4000 − 4500 | 16 |
| 4500 − 5000 | 7 |
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10 – 14 | 14 – 18 | 18 – 22 | 22 – 26 | 26 – 30 | 30 – 34 | 34 – 38 | 38 – 42 |
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For the following distribution
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| Less than 20 | 4 |
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the modal class is?
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∴ The mode of the volume of petrol filled is `square`.
