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प्रश्न
The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:
Lifetimes (in hours) | 0 − 20 | 20 − 40 | 40 − 60 | 60 − 80 | 80 − 100 | 100− 120 |
Frequency | 10 | 35 | 52 | 61 | 38 | 29 |
Determine the modal lifetimes of the components.
उत्तर
From the data given above, it can be observed that the maximum class frequency is 61, belonging to the class interval 60 − 80.
Therefore, modal class = 60 − 80
Lower class limit (l) of modal class = 60
Frequency (f1) of modal class = 61
Frequency (f0) of class preceding the modal class = 52
Frequency (f2) of class succeeding the modal class = 38
Class size (h) = 20
`"Mode" = l+((f_1-f_0)/(2f_1-f_0-f_2))xxh`
= `60+((61-52)/(2(61)-52-38))xx20`
= `60+(9/(122-90))(20)`
= `60+90/16`
= 60 + 5.625
= 65.625
Therefore, the modal lifetime of electrical components is 65.625 hours.
संबंधित प्रश्न
The following data gives the distribution of total monthly household expenditure of 200 families of a village. Find the modal monthly expenditure of the families. Also, find the mean monthly expenditure.
Expenditure (in Rs) | Number of families |
1000 − 1500 | 24 |
1500 − 2000 | 40 |
2000 − 2500 | 33 |
2500 − 3000 | 28 |
3000 − 3500 | 30 |
3500 − 4000 | 22 |
4000 − 4500 | 16 |
4500 − 5000 | 7 |
The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.
Runs scored | Number of batsmen |
3000 − 4000 | 4 |
4000 − 5000 | 18 |
5000 − 6000 | 9 |
6000 − 7000 | 7 |
7000 − 8000 | 6 |
8000 − 9000 | 3 |
9000 − 10000 | 1 |
10000 − 11000 | 1 |
Find the mode of the data.
Find the mode of the following data:
3, 5, 7, 4, 5, 3, 5, 6, 8, 9, 5, 3, 5, 3, 6, 9, 7, 4
Compare the modal ages of two groups of students appearing for an entrance test:
Age (in years): | 16-18 | 18-20 | 20-22 | 22-24 | 24-26 |
Group A: | 50 | 78 | 46 | 28 | 23 |
Group B: | 54 | 89 | 40 | 25 | 17 |
Find the mean, median and mode of the following data:
Classes: | 0-20 | 20-40 | 40-60 | 40-60 | 80-100 | 100-120 | 120-140 |
Frequency: | 6 | 8 | 10 | 12 | 6 | 5 | 3 |
If the mode of the data: 64, 60, 48, x, 43, 48, 43, 34 is 43, then x + 3 =
If the mode of the data: 16, 15, 17, 16, 15, x, 19, 17, 14 is 15, then x =
If mode of a series exceeds its mean by 12, then mode exceeds the median by
Find the mode of the following data:
Marks | 0 − 10 | 10 − 20 | 20 − 30 | 30 − 40 | 40 − 50 |
Number of students | 22 | 38 | 46 | 34 | 20 |
For the following distribution
Marks | No. of students |
Less than 20 | 4 |
Less than 40 | 12 |
Less than 60 | 25 |
Less than 80 | 56 |
Less than 100 | 74 |
Less than 120 | 80 |
the modal class is?
For the following distribution
C.I. | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
F | 20 | 30 | 24 | 40 | 18 |
the sum of lower limits of the modal class and the median class is?
Mode is the ______.
Find the mode of the following data.
Class interval | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
Frequency | 7 | 13 | 14 | 5 | 11 |
The weight of coffee in 70 packets are shown in the following table:
Weight (in g) | Number of packets |
200 – 201 | 12 |
201 – 202 | 26 |
202 – 203 | 20 |
203 – 204 | 9 |
204 – 205 | 2 |
205 – 206 | 1 |
Determine the modal weight.
If L = 10, f1 = 70, f0 = 58, f2 = 42, h = 2, then find the mode by using formula.
From one footwear shop, 12 pairs of chappals were sold. The sizes of these chappals are given below.
7, 8, 6, 7, 7, 5, 9, 7, 6, 7, 8, 7
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For the following frequency distribution, find the mode:
Class | 25 – 30 | 30 – 35 | 35 – 40 | 40 – 45 | 45 – 50 |
Frequency | 12 | 5 | 14 | 8 | 9 |
The mode of the numbers 2, 3, 3, 4, 5, 4, 4, 5, 3, 4, 2, 6, 7 is ______.
The following frequency distribution table shows the classification of the number of vehicles and the volume of petrol filled in them. To find the mode of the volume of petrol filled, complete the following activity:
Class (Petrol filled in Liters) |
Frequency (Number of Vehicles) |
0.5 - 3.5 | 33 |
3.5 - 6.5 | 40 |
6.5 - 9.5 | 27 |
9.5 - 12.5 | 18 |
12.5 - 15.5 | 12 |
Activity:
From the given table,
Modal class = `square`
∴ Mode = `square + [(f_1 - f_0)/(2f_1 -f_0 - square)] xx h`
∴ Mode = `3.5 + [(40 - 33)/(2(40) - 33 - 27)] xx square`
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∴ Mode = `square`
∴ The mode of the volume of petrol filled is `square`.