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The following data gives the information on the observed lifetimes (in hours) of 225 electrical components: Lifetimes (in hours)0 − 2020 − 4040 − 6060 − 8080 − 100100− 120 - Mathematics

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Question

The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:

Lifetimes (in hours) 0 − 20 20 − 40 40 − 60 60 − 80 80 − 100 100− 120
Frequency 10  35  52  61  38  29 

Determine the modal lifetimes of the components.

Sum

Solution

From the data given above, it can be observed that the maximum class frequency is 61, belonging to the class interval 60 − 80.

Therefore, modal class = 60 − 80

Lower class limit (l) of modal class = 60

Frequency (f1) of modal class = 61

Frequency (f0) of class preceding the modal class = 52

Frequency (f2) of class succeeding the modal class = 38

Class size (h) = 20

`"Mode" = l+((f_1-f_0)/(2f_1-f_0-f_2))xxh`

= `60+((61-52)/(2(61)-52-38))xx20`

= `60+(9/(122-90))(20)`

= `60+90/16`

= 60 + 5.625

= 65.625

Therefore, the modal lifetime of electrical components is 65.625 hours.

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Chapter 14: Statistics - Exercise 14.2 [Page 275]

APPEARS IN

NCERT Mathematics [English] Class 10
Chapter 14 Statistics
Exercise 14.2 | Q 2 | Page 275
RD Sharma Mathematics [English] Class 10
Chapter 15 Statistics
Exercise 15.5 | Q 8 | Page 46

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