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प्रश्न
Compute P(X = k) for the binomial distribution, B(n, p) where
n = 6, p = `1/3`, k = 3
उत्तर
P(X = x) = `""^"n""C"_x "p"^x "q"^("n" - x)`
x = 0, 1, 2, ...., n
p = `1/3`
q = 1 – p
= `1 - 1/3`
= `2/3`
P(X = 3) = `""^6"C"_3 (1/3)^2 (2/3)^3`
= `(6 xx 5 xx 4)/(3 xx 2) xx 1/27 xx 8/27`
= `160/729`
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