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प्रश्न
Consider the D−T reaction (deuterium−tritium fusion)
\[\ce{^2_1H + ^3_1H -> ^4_2He + n}\]
Calculate the energy released in MeV in this reaction from the data:
`"m"(""_1^2"H")`= 2.014102 u
`"m"(""_1^3"H")`= 3.016049 u
उत्तर
Take the D-T nuclear reaction: \[\ce{^2_1H + ^3_1H -> ^4_2He + n}\]
It is given that:
Mass of `""_1^2"H"` m1= 2.014102 u
Mass of `""_1^3"H"` m2 = 3.016049 u
Mass of `""_2^4"He"` m3 = 4.002603 u
Mass of `""_0^1"n"` m4 = 1.008665 u
Q-value of the given D-T reaction is:
Q = [m1 + m2 − m3 − m4] c2
= [2.014102 + 3.016049 − 4.002603 − 1.008665] c2
= [0.018883 c2] u
But 1 u = 931.5 MeV/c2
∴Q = 0.018883 × 931.5 = 17.59 MeV
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