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Convert the following: 2-Chloropropane to propan-1-ol - Chemistry

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प्रश्न

Convert the following:

2-Chloropropane to propan-1-ol

एक पंक्ति में उत्तर

उत्तर

\[\begin{array}{cc}
\ce{H3C - CH - CH3 ->[Alc.KOH]\underset{Propene}{H3C - CH = CH2}->[HBr][Peroxide]\underset{1-Bromopropane}{H3C - CH2 - CH2Br}->[NaOH(aq.)]\underset{Propan-1-ol}{H3C - CH2 - CH2OH}}\\
|\phantom{...........................................................................................}\\
\ce{\underset{2-Chloropropane}{Cl}\phantom{..........................................................................................}}
\end{array}\]

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अध्याय 10: Halogen Derivatives - Exercises [पृष्ठ २३३]

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बालभारती Chemistry [English] 12 Standard HSC
अध्याय 10 Halogen Derivatives
Exercises | Q 6. v. | पृष्ठ २३३

संबंधित प्रश्न

from the following pair would undergo SN2 faster from the other?

a.     b.


Complete the following reaction giving major products.

\[\begin{array}{cc}\ce{CH3 - CH - CH3 ->[Red P/Br2] A ->[Ag2O/H2O]B}\\|\phantom{.........................}\\
\ce{OH\phantom{.......................}}\end{array}\]


Name the reagent used to bring about the following conversion.

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Observe the following and answer the question given below.

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\[\ce{C6H5CH2Cl + KCN(alc) -> X + Y}\]

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Complete the following reaction giving major products.

\[\begin{array}{cc}
\ce{CH3}\phantom{.......}\\
|\phantom{.........}\\
\ce{CH3 - c - CH2 - Cl ->[Na/dry ether]}\\
|\phantom{.........}\\
\ce{CH3}\phantom{.......}
\end{array}\]


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Complete the following reaction, giving a major product.

\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{................}
\end{array}\]


Give a reason for the following:

Ethoxy ethane with conc. HI at 373 K gives C2H5OH and CH3I but not CH3OH and C2H5I.


Complete the following reaction giving major product.

\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{.................}\\
\end{array}\]


Complete the following reaction giving major product.

\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{................}\\
\end{array}\]


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