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प्रश्न
Write the product formed when alkyl halide reacts with silver nitrite.
उत्तर
\[\ce{\underset{(Alkyl halide)}{R - X} + \underset{(Silver nitrite)}{Ag NO2} -> \underset{Nitroalkane}{R - NO2 + Ag - X}}\]
Nitroalkane is formed when alkyl halide reacts with silver nitrite.
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संबंधित प्रश्न
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a. 
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\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{..................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{..................}\\
\ce{CH3}\phantom{................}
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl ->[Na/dry ether] A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{.................}
\end{array}\]
Complete the following reaction giving major product.
\[\begin{array}{cc}
\ce{CH3}\phantom{................}\\
|\phantom{...................}\\
\ce{CH3 - C - CH2 - Cl->[Na/ dry ether]A}\\
|\phantom{...................}\\
\ce{CH3}\phantom{................}\\
\end{array}\]
