हिंदी

The value of [H3O+] in mol lit–1 of 0.001 M acetic acid solution (Ka = 1.8 × 10–5) is ______. - Chemistry

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प्रश्न

The value of [H3O+] in mol lit–1 of 0.001 M acetic acid solution (Ka = 1.8 × 10–5) is ______.

विकल्प

  • 1.34 × 10–1

  • 1.34 × 10–2

  • 1.34 × 10–3

  • 1.34 × 10–4

MCQ
रिक्त स्थान भरें

उत्तर

The value of [H3O+] in mol lit–1 of 0.001 M acetic acid solution (Ka = 1.8 × 10–5) is 1.34 × 10–4

Explanation:

[H+] or [H3O+] = αc

c = 0.001 M

= 10–3 M

α = `sqrt(K_a/c)`  ......[∵ Ka = α2c]

= `sqrt((1.8 xx 10^-5)/10^-3)`

= 1.34 × 10–1 

Now [H3O+] = α × c

= 1.34 × 10–1 × 10–3

= 1.34 × 10–4

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Electrical Conductance of Solution
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2021-2022 (March) Set 1

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