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प्रश्न
The value of [H3O+] in mol lit–1 of 0.001 M acetic acid solution (Ka = 1.8 × 10–5) is ______.
पर्याय
1.34 × 10–1
1.34 × 10–2
1.34 × 10–3
1.34 × 10–4
उत्तर
The value of [H3O+] in mol lit–1 of 0.001 M acetic acid solution (Ka = 1.8 × 10–5) is 1.34 × 10–4.
Explanation:
[H+] or [H3O+] = αc
c = 0.001 M
= 10–3 M
α = `sqrt(K_a/c)` ......[∵ Ka = α2c]
= `sqrt((1.8 xx 10^-5)/10^-3)`
= 1.34 × 10–1
Now [H3O+] = α × c
= 1.34 × 10–1 × 10–3
= 1.34 × 10–4
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