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प्रश्न
The molar conductivity of 0.05 M BaCl2 solution at 25° C is 223Ω-1 cm2 mol-1. What is its conductivity?
उत्तर
C = 0.05 M
λm = 223Ω-1 cm2 mol-1
λm = `(1000"k")/"C"`
`therefore "k" = (λ_"m" xx "C")/1000`
`= (223 xx 0.05)/1000`
= 0.01115 S cm-1
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