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प्रश्न
Differentiate sin2x with respect to x2.
योग
उत्तर
Let u = (sin x)2 ; v = x2
`"du"/"dx"` = (2 sin x) (cos x) = sin 2x ; `"dv"/"dx"` = 2x
`"du"/"dv" = ("du"/"dx")/("dv"/"dx") = (sin 2x)/(2x)`
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