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प्रश्न
Differentiate the following w.r.t. x:
`log(cos e^x)`
उत्तर
Let, y = log (cos `e^x`)
Differentiating both sides with respect to x,
`dy/dx= d/dx (cos e^x)`
`= 1/(cos e^x) d/dx (cos e^x)`
`= 1/(cos e^x) (- sin e^x) d/dx e^x `
`= - (sin e^x)/(cos e^x) * e^x`
`= - e^x tan e^x`
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