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प्रश्न
Divide −4a3 + 4a2 + a by 2a.
योग
उत्तर
\[\frac{- 4 a^3 + 4 a^2 + a}{2a}\]
\[ = \frac{- 4 a^3}{2a} + \frac{4 a^2}{2a} + \frac{a}{2a}\]
\[ = - 2 a^{(3 - 1)} + 2 a^{(2 - 1)} + \frac{1}{2}\]
\[ = - 2 a^2 + 2a + \frac{1}{2}\]
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