Advertisements
Advertisements
प्रश्न
Draw the graph of the equation given below.
2x + y = 1
उत्तर
The equation of the given line is 2x + y = 1.
∴ 2x + y = 1
⇒ y = 1 − 2x ...(1)
Putting x = 0 in (1), we get
y = 1 − 2 × 0
y = 1 − 0
y = 1
Putting x = 1 in (1), we get
y = 1 − 2 × 1
y = 1 − 2
y = −1
Putting x = −1 in (1), we get
y = 1 − 2 × (−1)
y = 1 + 2
y = 3
Putting x = 2 in (1), we get
y = 1 − 2 × 2
y = 1 − 4
y = −3
These values can be represented in the table in the form of ordered pairs as follows:
x | 0 | 1 | -1 | 2 |
y | 1 | -1 | 3 | -3 |
(x, y) | (0, 1) | (1, -1) | (-1, 3) | (2, -3) |
∴ The line is the graph of the equation 2x + y = 1.
APPEARS IN
संबंधित प्रश्न
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
Draw the graph for the linear equation given below:
x + 3 = 0
Draw the graph for the linear equation given below:
x = 0
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
y = - x + 4
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
Draw the graph of the equation 3x - 4y = 12.
Use the graph drawn to find:
(i) y1, the value of y, when x = 4.
(ii) y2, the value of y, when x = 0.
Draw a graph of each of the following equations: 5x + 2y = 16
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.