Advertisements
Advertisements
प्रश्न
Evaluate:
(−3)−2
योग
उत्तर
\[( - 3 )^2 = \frac{1}{3^2}\] → (a−n = 1/(an))
\[= \frac{1}{9}\]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Evaluate:
\[\left( \frac{1}{3} \right)^{- 4}\]
Simplify:
\[\left( 4^{- 1} - 5^{- 1} \right) \div 3^{- 1}\]
Simplify:
\[\left\{ \left( \frac{1}{2} \right)^{- 1} \times ( - 4 )^{- 1} \right\}^{- 1}\]
By what number should (−15)−1 be divided so that the quotient may be equal to (−5)−1?
By what number should \[\left( \frac{5}{3} \right)^{- 2}\] be multiplied so that the product may be \[\left( \frac{7}{3} \right)^{- 1} ?\]
Find x, if
\[\left( \frac{- 1}{2} \right)^{- 19} \times \left( \frac{- 1}{2} \right)^8 = \left( \frac{- 1}{2} \right)^{- 2x + 1}\]
For any two non-zero rational numbers a and b, a4 ÷ b4 is equal to
Find the value of `(1/2)^(-2)+(1/3)^(-2)+(1/4)^(-2)`
The multiplicative inverse of `(- 5/9)^99` is ______.
The multiplicative inverse of `(3/2)^2` is not equal to `(2/3)^-2`.