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प्रश्न
Evaluate : `int sec^2x/(cosec^2x)dx`
उत्तर
`I = int(sec^2x)/(cosec^2x) dx`
`I = int (sin^2 x)/(cos^2 x)dx`
`I = int tan^2x dx= int sec^2 x dx - int dx `
`I= tan x - x + c`
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