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प्रश्न
Evaluate: ` int tan^3x "dx"`
उत्तर
`int tan^3 x "dx" = int tan"x"(tan^2"x") "dx"`
`= int tan"x" (sec^2"x"-1) "dx"`
`= int tan"x"sec^2"x" "dx"- int tan"x" "dx"`
`=tan^2 "x"/2 + log |cos "x"| +"C"`
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