Advertisements
Advertisements
प्रश्न
Evaluate the following Limits: `lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x))]`
उत्तर
`lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x))]`
= `lim_(x -> 3)[(x - 3)/(sqrt(x - 2) - sqrt(4 - x)) xx(sqrt(x - 2) + sqrt(4 - x))/(sqrt(x - 2) + sqrt(4 - x))]`
= `lim_(x ->3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/((x - 2) - (4 - x)`
= `lim_(x -> 3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/(2x - 6)`
= `lim_(x -> 3) ((x - 3)(sqrt(x - 2) + sqrt(4 - x)))/(2(x - 3)`
= `lim_(x -> 3) (sqrt(x - 2) + sqrt(4 - x))/2 ...[("As" x -> 3"," x ≠ 3),(therefore x - 3 ≠ 0)]`
= `1/2 lim_(x -> 3)(sqrt(x - 2) + sqrt(4 - x))`
= `1/2(sqrt(3 - 2) + sqrt(4 - 3))`
= `1/2(1 + 1)`
= 1
APPEARS IN
संबंधित प्रश्न
Evaluate the following limits: `lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`
Evaluate the following limit:
`lim_(z -> 2) [(z^2 - 5z + 6)/(z^2 - 4)]`
Evaluate the following limit :
`lim_(x -> -3)[(x + 3)/(x^2 + 4x + 3)]`
Evaluate the following limit :
`lim_(y -> 0)[(5y^3 + 8y^2)/(3y^4 - 16y^2)]`
Evaluate the following limit :
`lim_(x -> 2)[(x^3 - 4x^2 + 4x)/(x^2 - 1)]`
Evaluate the following limit :
`lim_(Deltax -> 0) [((x + Deltax)^2 - 2(x + Deltax) + 1 - (x^2 - 2x + 1))/(Deltax)]`
Evaluate the following limit :
`lim_(x -> 2) [(x^3 - 7x + 6)/(x^3 - 7x^2 + 16x - 12)]`
Evaluate the following limit :
`lim_(x -> 1) [(x^4 - 3x^2 + 2)/(x^3 - 5x^2 + 3x + 1)]`
Select the correct answer from the given alternatives.
`lim_(x -> -2)((x^7 + 128)/(x^3 + 8))` =
Evaluate the following limits
`lim_(x->-2) [(x^7 + x^5 + 160 )/(x^3 + 8)]`
Evaluate the following limit :
`lim_(x->-2)[(x^7 + x^5 +160)/(x^3+8)]`
Evaluate the following
Limit: `lim_(x->1) [(x^3 - 1 )/ (x^2 + 5x -6)]`
Evaluate the following limit:
`lim_(x->-2) [(x^7 + x^5 + 160)/(x^3 + 8)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`
Evaluate the following limit :
`lim_(x->-2)[(x^7 + x^5 +160)/(x^3 +8)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3 -1)/(x^2 +5x -6)]`
Evaluate the following limit:
`lim_(x->-2) [(x^7 + x^5 +160)/(x^3 + 8)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3-1)/(x^2+5x-6)]`
Evaluate the following Limit.
`lim_(x->1)[(x^3 - 1)/(x^2 + 5x - 6)]`