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प्रश्न
Explain how and why will the rate of reaction for a given reaction be affected when a catalyst is added.
उत्तर
The rate of reaction will increase. The catalyst decreases the activation energy of the reaction therefore the reaction becomes faster.
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संबंधित प्रश्न
For a reaction
\[\ce{2H2O2->[I^-][Alkaline medium]2H2O + O2}\]
The Proposed mechanism is given below:
(1) H2O2+I- → H2O+IO-(slow)
(2) H2O2+IO-→H2O+I-+O2(fast)
(i) Write the rate law for the reaction.
(ii) Write the overall order of a reaction.
(iii) Out of steps(1) and (2), which one is the rate-determining step?
Which of the following statements regarding catalyst is FALSE?
____________ is used as a catalyst for the following reaction:
\[\ce{CO + \underset{\text{(Steam)}}{H2O} ⇌ CO2 + H2}\]
In the manufacture of ammonia by Haber's process, Al2O3 does not act as a catalyst but increases the activity of the catalyst. The role of Al2O3 can be best described as ____________.
Which of the following is a character of catalyst?
For a certain reaction large fraction of molecules has energy more than the threshold energy, yet the rate of reaction is very slow. Why?
Match the items of Column I and Column II.
| Column I | Column II | |
| (i) | Diamond | (a) short interval of time |
| (ii) | Instantaneous rate | (b) ordinarily rate of conversion is imperceptible |
| (iii) | Average rate | (c) long duration of time |
Describe how does the enthalpy of reaction remain unchanged when a catalyst is used in the reaction.
For the reaction 3A `rightarrow` 2B, rate of reaction `+ (d[B])/(dt)` is equal to ______.
For the reaction \[\ce{3A -> 2B}\], rate of reaction `-("d"["A"])/"dt"` is equal to ______.
