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प्रश्न
Express 81 as the sum of first nine consecutive odd numbers.
उत्तर
The first nine consecutive odd numbers are 1, 3, 5, 7, 9, 11, 13, 15 and 17.
We have: 81
As, 81 is a perfect square.
So, 81 = (9)2
= 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17
= Sum of first nine consecutive odd numbers.
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संबंधित प्रश्न
The squares of which of the following would be odd numbers?
- 431
- 2826
- 7779
- 82004
Observe the following pattern and find the missing digits.
112 = 121
1012 = 10201
10012 = 1002001
1000012 = 1 ______ 2 ______ 1
100000012 = ______
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
Express 49 as the sum of 7 odd numbers.
Express 121 as the sum of 11 odd numbers.
Is 24 a square number?
The sum of first six odd natural numbers is ______.
The sum of first n odd natural numbers is n2.
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
