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प्रश्न
The sum of first six odd natural numbers is ______.
उत्तर
The sum of first six odd natural numbers is 36.
Explanation:
∵ Every square can be expressed as a sum of successive odd natural numbers from 1.
⇒ The sum of first n odd natural numbers is n2
Here, n = 6
⇒ 1 + 3 + 5 + 7 + 9 + 11
= 6 × 6
= 36
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संबंधित प्रश्न
The squares of which of the following would be odd numbers?
- 431
- 2826
- 7779
- 82004
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
Express 49 as the sum of 7 odd numbers.
How many numbers lie between squares of the following numbers?
99 and 100
64 is the square number of __________
A number multiplied by _________ is called square of that number
Fill in the blank box.
The sum of first n odd natural numbers is n2.
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
