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प्रश्न
The sum of first six odd natural numbers is ______.
उत्तर
The sum of first six odd natural numbers is 36.
Explanation:
∵ Every square can be expressed as a sum of successive odd natural numbers from 1.
⇒ The sum of first n odd natural numbers is n2
Here, n = 6
⇒ 1 + 3 + 5 + 7 + 9 + 11
= 6 × 6
= 36
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संबंधित प्रश्न
The squares of which of the following would be odd numbers?
- 431
- 2826
- 7779
- 82004
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19
Express 49 as the sum of 7 odd numbers.
Express 121 as the sum of 11 odd numbers.
How many numbers lie between squares of the following numbers?
99 and 100
64 is the square number of __________
Is 24 a square number?
Fill in the blank box.
The sum of first n odd natural numbers is n2.
