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प्रश्न
The sum of first n odd natural numbers is n2.
पर्याय
True
False
उत्तर
This statement is True.
Explanation:
Given: First n odd natural numbers
Odd natural numbers will be = 2n – 1
As we know, sum of odd natural numbers
= `(2 xx n xx (n + 1))/2 - n`
= n(n + 1) – n
= n2 + n – n
= n2
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संबंधित प्रश्न
The squares of which of the following would be odd numbers?
- 431
- 2826
- 7779
- 82004
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
How many numbers lie between squares of the given numbers?
12 and 13
How many numbers lie between squares of the given numbers?
25 and 26
64 is the square number of __________
A number multiplied by _________ is called square of that number
The sum of first six odd natural numbers is ______.
Express 81 as the sum of first nine consecutive odd numbers.
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
