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Question
The sum of first n odd natural numbers is n2.
Options
True
False
Solution
This statement is True.
Explanation:
Given: First n odd natural numbers
Odd natural numbers will be = 2n – 1
As we know, sum of odd natural numbers
= `(2 xx n xx (n + 1))/2 - n`
= n(n + 1) – n
= n2 + n – n
= n2
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RELATED QUESTIONS
Observe the following pattern and find the missing digits.
112 = 121
1012 = 10201
10012 = 1002001
1000012 = 1 ______ 2 ______ 1
100000012 = ______
Observe the following pattern and supply the missing number.
112 = 121
1012 = 10201
101012 = 102030201
10101012 = _____
____2 = 10203040504030201.
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding find the sum:
1 + 3 + 5 + 7 + 9
Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19
How many numbers lie between squares of the given numbers?
25 and 26
Square of the number 7 is _________
64 is the square number of __________
Fill in the blank box.
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
